Last Updated on November 16, 2023 by Electricalvolt

**Definition: **Magnetomotive force (MMF) is the **magnetic pressure** that sets up the magnetic flux in the magnetic circuit. Without MMF, it is not possible to set up flux in the magnetic circuit. The MMF in a magnetic circuit is analogous to the electromotive force in an electric circuit.

The electromotive force accelerates the electrons and thus the current flows in the electric circuit. Similarly, the MMF set up flux in the magnetic circuit. The magnitude of the flux in a magnetic circuit depends on the **magnetomotive force** and the reluctance of the magnetic circuit. The MMF of the magnetic circuit depends on the number of turns in a coil and the magnitude of the current. We denote the MMF by the letter F.

**Formula of MMF**

**The formula of MMF** is given below.

**F = NI **

Where N- Number of turns and I is the current

**Unit of MMF**

The **SI unit of the MMF** is **Ampere-turn (AT)** & its** CGS unit is G (gilbert).**

Let us understand the **meaning of MMF** by taking an example of a coil wound on magnetic material.

**Magnetomotive Force of Inductive Coil**

The MMF for the inductive coil shown in the figure below is expressed as

Where, N – numbers of turns of the inductive coil

I – current

The strength of the MMF is equal to the product of the current flowing in a coil and the number of turns. The work is done in moving the unit magnetic pole(1 weber) in a magnetic circuit.

MMF is the magnetic potential that sets up the flux in the magnetic circuit.

Flux = MMF/ Reluctance

MMF = Flux X Reluctance

**F= Φ X R _{m}**

The opposition offered by a magnetic material is the magnetic reluctance.

**Solved Problems on MMF **

**A coil of 100 turns is wound uniformly over a wooden ring that **carries a **2-ampere current. Calculate MMF?**

F = NI

= 100 x 2

= **200 AT**

**Calculate the magnetomotive force required to produce a flux of 0.020 Wbacross an air-gap 2.0 mm long, having an effective area of 200 cm ^{2}**

ϕ = 0.020 Wb, l = 2.0 mm = 2.0×10^{-3} m, A = 200 cm2 = 2×10^{-2} m^{2}

B = ϕ / A

= 0.020 / (2×10^{-2})

= 1 T

H = B / μ0

=1 / (4π×10^{-7})

= 7.96×10^{5} A/m**F (MMF) **= H.l = 7.97×10^{5} × 2.0 ×10^{-3} = **1.59×10 ^{3} AT**

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